Base | Representation |
---|---|
bin | 1100000110001110001010… |
… | …0101110110100011011101 |
3 | 1202002120020222100021200210 |
4 | 3001203202211312203131 |
5 | 3220410442200301023 |
6 | 44142223202443033 |
7 | 2541652453204554 |
oct | 301434245664335 |
9 | 52076228307623 |
10 | 13301020322013 |
11 | 4268a27240026 |
12 | 15a99b0963479 |
13 | 756385cbb058 |
14 | 33dab6884d9b |
15 | 180ecb6dd593 |
hex | c18e29768dd |
13301020322013 has 32 divisors (see below), whose sum is σ = 18203963057280. Its totient is φ = 8635898511360.
The previous prime is 13301020321999. The next prime is 13301020322041. The reversal of 13301020322013 is 31022302010331.
13301020322013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13301020322013 - 210 = 13301020320989 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301020322113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7424995 + ... + 9040607.
It is an arithmetic number, because the mean of its divisors is an integer number (568873845540).
Almost surely, 213301020322013 is an apocalyptic number.
It is an amenable number.
13301020322013 is a deficient number, since it is larger than the sum of its proper divisors (4902942735267).
13301020322013 is a wasteful number, since it uses less digits than its factorization.
13301020322013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1616109.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13301020322013 its reverse (31022302010331), we get a palindrome (44323322332344).
The spelling of 13301020322013 in words is "thirteen trillion, three hundred one billion, twenty million, three hundred twenty-two thousand, thirteen".
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