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133010222113 = 433307182961
BaseRepresentation
bin111101111100000000…
…1101110110000100001
3110201022201012101001201
41323320001232300201
54134401104101423
6141034250401201
712416055143056
oct1737001566041
9421281171051
10133010222113
11514558915aa
1221940a30201
13c709727a52
14661b1b302d
1536d72762ad
hex1ef806ec21

133010222113 has 4 divisors (see below), whose sum is σ = 133317405508. Its totient is φ = 132703038720.

The previous prime is 133010222083. The next prime is 133010222123. The reversal of 133010222113 is 311222010331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35377095744 + 97633126369 = 188088^2 + 312463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133010222113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133010222123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153591048 + ... + 153591913.

It is an arithmetic number, because the mean of its divisors is an integer number (33329351377).

Almost surely, 2133010222113 is an apocalyptic number.

It is an amenable number.

133010222113 is a deficient number, since it is larger than the sum of its proper divisors (307183395).

133010222113 is an equidigital number, since it uses as much as digits as its factorization.

133010222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 307183394.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 133010222113 its reverse (311222010331), we get a palindrome (444232232444).

The spelling of 133010222113 in words is "one hundred thirty-three billion, ten million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 433 307182961 133010222113