Base | Representation |
---|---|
bin | 1100000110001110001101… |
… | …0110010101011001110011 |
3 | 1202002120021212020222112111 |
4 | 3001203203112111121303 |
5 | 3220411003424000113 |
6 | 44142224335110151 |
7 | 2541652666220044 |
oct | 301434326253163 |
9 | 52076255228474 |
10 | 13301033031283 |
11 | 4268a33430758 |
12 | 15a99b5072357 |
13 | 75638881ab2a |
14 | 33dab84328cb |
15 | 180ecc89e13d |
hex | c18e3595673 |
13301033031283 has 2 divisors, whose sum is σ = 13301033031284. Its totient is φ = 13301033031282.
The previous prime is 13301033031259. The next prime is 13301033031301. The reversal of 13301033031283 is 38213033010331.
13301033031283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (38213033010331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13301033031283 - 29 = 13301033030771 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301063031283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650516515641 + 6650516515642.
It is an arithmetic number, because the mean of its divisors is an integer number (6650516515642).
Almost surely, 213301033031283 is an apocalyptic number.
13301033031283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301033031283 is an equidigital number, since it uses as much as digits as its factorization.
13301033031283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 13301033031283 in words is "thirteen trillion, three hundred one billion, thirty-three million, thirty-one thousand, two hundred eighty-three".
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