1330111141041 has 4 divisors (see below), whose sum is σ = 1773481521392. Its totient is φ = 886740760692.

The previous prime is 1330111140949. The next prime is 1330111141049. The reversal of 1330111141041 is 1401411110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1330111141041 - 2⁹ = 1330111140529 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330111140999 and 1330111141017.

It is not an unprimeable number, because it can be changed into a prime (1330111141049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221685190171 + ... + 221685190176.

It is an arithmetic number, because the mean of its divisors is an integer number (443370380348).

Almost surely, 2^{1330111141041} is an apocalyptic number.

It is an amenable number.

1330111141041 is a deficient number, since it is larger than the sum of its proper divisors (443370380351).

1330111141041 is an equidigital number, since it uses as much as digits as its factorization.

1330111141041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443370380350.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 1330111141041 its reverse (1401411110331), we get a palindrome (2731522251372).

The spelling of 1330111141041 in words is "one trillion, three hundred thirty billion, one hundred eleven million, one hundred forty-one thousand, forty-one".