Base | Representation |
---|---|
bin | 10011010110110000110… |
… | …011101001000100000011 |
3 | 11201011020201221000112022 |
4 | 103112300303221010003 |
5 | 133243031433101034 |
6 | 2455013351352055 |
7 | 165045252561566 |
oct | 23266063510403 |
9 | 4634221830468 |
10 | 1330111222019 |
11 | 473108121a48 |
12 | 19594b68262b |
13 | 98576531b88 |
14 | 485406a64dd |
15 | 248ec6bdb2e |
hex | 135b0ce9103 |
1330111222019 has 2 divisors, whose sum is σ = 1330111222020. Its totient is φ = 1330111222018.
The previous prime is 1330111222007. The next prime is 1330111222051. The reversal of 1330111222019 is 9102221110331.
It is a weak prime.
It is an emirp because it is prime and its reverse (9102221110331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1330111222019 - 236 = 1261391745283 is a prime.
It is a super-2 number, since 2×13301112220192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1330111272019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665055611009 + 665055611010.
It is an arithmetic number, because the mean of its divisors is an integer number (665055611010).
Almost surely, 21330111222019 is an apocalyptic number.
1330111222019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330111222019 is an equidigital number, since it uses as much as digits as its factorization.
1330111222019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 1330111222019 in words is "one trillion, three hundred thirty billion, one hundred eleven million, two hundred twenty-two thousand, nineteen".
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