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13301113520203 is a prime number
BaseRepresentation
bin1100000110001110100000…
…1001011000000001001011
31202002120111110201020120121
43001203220021120001023
53220411140030121303
644142240332204111
72541654664320445
oct301435011300113
952076443636517
1013301113520203
114268a74906223
1215a9a18009637
1375639c3bc902
1433dac4dc5495
15180ed499c9bd
hexc18e825804b

13301113520203 has 2 divisors, whose sum is σ = 13301113520204. Its totient is φ = 13301113520202.

The previous prime is 13301113520161. The next prime is 13301113520221. The reversal of 13301113520203 is 30202531110331.

It is a strong prime.

It is an emirp because it is prime and its reverse (30202531110331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13301113520203 - 217 = 13301113389131 is a prime.

It is a super-2 number, since 2×133011135202032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13301113520803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650556760101 + 6650556760102.

It is an arithmetic number, because the mean of its divisors is an integer number (6650556760102).

Almost surely, 213301113520203 is an apocalyptic number.

13301113520203 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301113520203 is an equidigital number, since it uses as much as digits as its factorization.

13301113520203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 13301113520203 its reverse (30202531110331), we get a palindrome (43503644630534).

The spelling of 13301113520203 in words is "thirteen trillion, three hundred one billion, one hundred thirteen million, five hundred twenty thousand, two hundred three".