13301131001233 has 4 divisors (see below), whose sum is σ = 13304504358208. Its totient is φ = 13297757644260.

The previous prime is 13301131001231. The next prime is 13301131001297. The reversal of 13301131001233 is 33210013110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13301131001233 - 2¹ = 13301131001231 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301131001231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1686672573 + ... + 1686680458.

It is an arithmetic number, because the mean of its divisors is an integer number (3326126089552).

Almost surely, 2^{13301131001233} is an apocalyptic number.

It is an amenable number.

13301131001233 is a deficient number, since it is larger than the sum of its proper divisors (3373356975).

13301131001233 is an equidigital number, since it uses as much as digits as its factorization.

13301131001233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3373356974.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13301131001233 its reverse (33210013110331), we get a palindrome (46511144111564).

The spelling of 13301131001233 in words is "thirteen trillion, three hundred one billion, one hundred thirty-one million, one thousand, two hundred thirty-three".