Base | Representation |
---|---|
bin | 1100000110001110100100… |
… | …1100111110011110111001 |
3 | 1202002120112201001120111021 |
4 | 3001203221030332132321 |
5 | 3220411204044211101 |
6 | 44142242204102441 |
7 | 2541655301045653 |
oct | 301435114763671 |
9 | 52076481046437 |
10 | 13301131241401 |
11 | 4268a8390a443 |
12 | 15a9a21b34a21 |
13 | 7563a2c85a23 |
14 | 33dac74b96d3 |
15 | 180ed62ed5a1 |
hex | c18e933e7b9 |
13301131241401 has 2 divisors, whose sum is σ = 13301131241402. Its totient is φ = 13301131241400.
The previous prime is 13301131241393. The next prime is 13301131241467. The reversal of 13301131241401 is 10414213110331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13117985759376 + 183145482025 = 3621876^2 + 427955^2 .
It is a cyclic number.
It is not a de Polignac number, because 13301131241401 - 23 = 13301131241393 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301131241501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650565620700 + 6650565620701.
It is an arithmetic number, because the mean of its divisors is an integer number (6650565620701).
Almost surely, 213301131241401 is an apocalyptic number.
It is an amenable number.
13301131241401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301131241401 is an equidigital number, since it uses as much as digits as its factorization.
13301131241401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 13301131241401 its reverse (10414213110331), we get a palindrome (23715344351732).
The spelling of 13301131241401 in words is "thirteen trillion, three hundred one billion, one hundred thirty-one million, two hundred forty-one thousand, four hundred one".
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