Base | Representation |
---|---|
bin | 11000110001100111… |
… | …10101011110001001 |
3 | 1021022222110002120222 |
4 | 30120303311132021 |
5 | 204220043042213 |
6 | 10035505355425 |
7 | 650420565554 |
oct | 143063653611 |
9 | 37288402528 |
10 | 13301143433 |
11 | 570616aa26 |
12 | 26b2638b75 |
13 | 133c8b0096 |
14 | 90275969b |
15 | 52cad9808 |
hex | 318cf5789 |
13301143433 has 4 divisors (see below), whose sum is σ = 13730212608. Its totient is φ = 12872074260.
The previous prime is 13301143421. The next prime is 13301143447. The reversal of 13301143433 is 33434110331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33434110331 = 3259 ⋅10259009.
It is a cyclic number.
It is not a de Polignac number, because 13301143433 - 218 = 13300881289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13301143403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214534541 + ... + 214534602.
It is an arithmetic number, because the mean of its divisors is an integer number (3432553152).
Almost surely, 213301143433 is an apocalyptic number.
It is an amenable number.
13301143433 is a deficient number, since it is larger than the sum of its proper divisors (429069175).
13301143433 is an equidigital number, since it uses as much as digits as its factorization.
13301143433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429069174.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 13301143433 its reverse (33434110331), we get a palindrome (46735253764).
The spelling of 13301143433 in words is "thirteen billion, three hundred one million, one hundred forty-three thousand, four hundred thirty-three".
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