Base | Representation |
---|---|
bin | 111101111100000100… |
… | …0111110111010101001 |
3 | 110201022211202222000020 |
4 | 1323320020332322221 |
5 | 4134402100421210 |
6 | 141034355231053 |
7 | 12416110251645 |
oct | 1737010767251 |
9 | 421284688006 |
10 | 133012123305 |
11 | 5145696aa36 |
12 | 219415a8489 |
13 | c709c42209 |
14 | 661b549c25 |
15 | 36d74ee770 |
hex | 1ef823eea9 |
133012123305 has 16 divisors (see below), whose sum is σ = 219684539904. Its totient is φ = 68651418240.
The previous prime is 133012123303. The next prime is 133012123327. The reversal of 133012123305 is 503321210331.
It is not a de Polignac number, because 133012123305 - 21 = 133012123303 is a prime.
It is a super-2 number, since 2×1330121233052 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133012123301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 143023324 + ... + 143024253.
It is an arithmetic number, because the mean of its divisors is an integer number (13730283744).
Almost surely, 2133012123305 is an apocalyptic number.
133012123305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133012123305 is a deficient number, since it is larger than the sum of its proper divisors (86672416599).
133012123305 is a wasteful number, since it uses less digits than its factorization.
133012123305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 286047616.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 133012123305 its reverse (503321210331), we get a palindrome (636333333636).
The spelling of 133012123305 in words is "one hundred thirty-three billion, twelve million, one hundred twenty-three thousand, three hundred five".
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