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1330124013433 = 4398273366239
BaseRepresentation
bin10011010110110001100…
…100011011111101111001
311201011021121222220001101
4103112301210123331321
5133243043221412213
62455014525451401
7165045466365415
oct23266144337571
94634247886041
101330124013433
11473114369366
12195953a10b61
1398579090167
1448542275d45
15248ed898bdd
hex135b191bf79

1330124013433 has 8 divisors (see below), whose sum is σ = 1333318694400. Its totient is φ = 1326930082368.

The previous prime is 1330124013403. The next prime is 1330124013461. The reversal of 1330124013433 is 3343104210331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1330124013433 - 217 = 1330123882361 is a prime.

It is a super-2 number, since 2×13301240134332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330124013403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3448728 + ... + 3814966.

It is an arithmetic number, because the mean of its divisors is an integer number (166664836800).

Almost surely, 21330124013433 is an apocalyptic number.

It is an amenable number.

1330124013433 is a deficient number, since it is larger than the sum of its proper divisors (3194680967).

1330124013433 is an equidigital number, since it uses as much as digits as its factorization.

1330124013433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 374951.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 1330124013433 its reverse (3343104210331), we get a palindrome (4673228223764).

The spelling of 1330124013433 in words is "one trillion, three hundred thirty billion, one hundred twenty-four million, thirteen thousand, four hundred thirty-three".

Divisors: 1 439 8273 366239 3631847 160778921 3029895247 1330124013433