Base | Representation |
---|---|
bin | 10011010110110001111… |
… | …111000101101010011011 |
3 | 11201011022010010211202202 |
4 | 103112301333011222123 |
5 | 133243102013444323 |
6 | 2455015335320415 |
7 | 165045612644333 |
oct | 23266177055233 |
9 | 4634263124682 |
10 | 1330130999963 |
11 | 473118300457 |
12 | 19595622010b |
13 | 9857a6681bc |
14 | 485431740c3 |
15 | 248ee2c8d28 |
hex | 135b1fc5a9b |
1330130999963 has 2 divisors, whose sum is σ = 1330130999964. Its totient is φ = 1330130999962.
The previous prime is 1330130999947. The next prime is 1330131000043. The reversal of 1330130999963 is 3699990310331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330130999963 - 24 = 1330130999947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330130999899 and 1330130999908.
It is not a weakly prime, because it can be changed into another prime (1330130999903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665065499981 + 665065499982.
It is an arithmetic number, because the mean of its divisors is an integer number (665065499982).
Almost surely, 21330130999963 is an apocalyptic number.
1330130999963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330130999963 is an equidigital number, since it uses as much as digits as its factorization.
1330130999963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3188646, while the sum is 56.
The spelling of 1330130999963 in words is "one trillion, three hundred thirty billion, one hundred thirty million, nine hundred ninety-nine thousand, nine hundred sixty-three".
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