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133014214224553 is a prime number
BaseRepresentation
bin11110001111100111001000…
…111111010010101010101001
3122102222000221021211222122011
4132033213020333102222221
5114413301102320141203
61150521515245355521
740005650140654504
oct3617471077225251
9572860837758564
10133014214224553
1139423014290222
1212b03067268ba1
13592b256bbb93c
1424bbccabb413b
15105a011b3976d
hex78f9c8fd2aa9

133014214224553 has 2 divisors, whose sum is σ = 133014214224554. Its totient is φ = 133014214224552.

The previous prime is 133014214224443. The next prime is 133014214224569. The reversal of 133014214224553 is 355422412410331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108069913166224 + 24944301058329 = 10395668^2 + 4994427^2 .

It is a cyclic number.

It is not a de Polignac number, because 133014214224553 - 213 = 133014214216361 is a prime.

It is not a weakly prime, because it can be changed into another prime (133014214224253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66507107112276 + 66507107112277.

It is an arithmetic number, because the mean of its divisors is an integer number (66507107112277).

Almost surely, 2133014214224553 is an apocalyptic number.

It is an amenable number.

133014214224553 is a deficient number, since it is larger than the sum of its proper divisors (1).

133014214224553 is an equidigital number, since it uses as much as digits as its factorization.

133014214224553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 133014214224553 its reverse (355422412410331), we get a palindrome (488436626634884).

The spelling of 133014214224553 in words is "one hundred thirty-three trillion, fourteen billion, two hundred fourteen million, two hundred twenty-four thousand, five hundred fifty-three".