Base | Representation |
---|---|
bin | 1100000110010001110011… |
… | …1111000010011111000011 |
3 | 1202002122210020210020101012 |
4 | 3001210130333002133003 |
5 | 3220414444000044021 |
6 | 44142504320431135 |
7 | 2542015650310436 |
oct | 301443477023703 |
9 | 52078706706335 |
10 | 13302000003011 |
11 | 426938a245945 |
12 | 15aa024a784ab |
13 | 7564b0c62855 |
14 | 33db6aa2381d |
15 | 18103770935b |
hex | c191cfc27c3 |
13302000003011 has 2 divisors, whose sum is σ = 13302000003012. Its totient is φ = 13302000003010.
The previous prime is 13302000003007. The next prime is 13302000003031. The reversal of 13302000003011 is 11030000020331.
13302000003011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13302000003011 - 22 = 13302000003007 is a prime.
It is a super-2 number, since 2×133020000030112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13302000003031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651000001505 + 6651000001506.
It is an arithmetic number, because the mean of its divisors is an integer number (6651000001506).
Almost surely, 213302000003011 is an apocalyptic number.
13302000003011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13302000003011 is an equidigital number, since it uses as much as digits as its factorization.
13302000003011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13302000003011 its reverse (11030000020331), we get a palindrome (24332000023342).
The spelling of 13302000003011 in words is "thirteen trillion, three hundred two billion, three thousand, eleven".
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