Base | Representation |
---|---|
bin | 11110001111101101000001… |
… | …001001011111011000000011 |
3 | 122102222122020002221021010212 |
4 | 132033231001021133120003 |
5 | 114413402013413200032 |
6 | 1150524441410144335 |
7 | 40006262421536444 |
oct | 3617550111373003 |
9 | 572878202837125 |
10 | 133020525131267 |
11 | 39425762664904 |
12 | 12b043288820ab |
13 | 592ba21503977 |
14 | 24bc328dd52cb |
15 | 105a280bd7bb2 |
hex | 78fb4125f603 |
133020525131267 has 2 divisors, whose sum is σ = 133020525131268. Its totient is φ = 133020525131266.
The previous prime is 133020525131231. The next prime is 133020525131281. The reversal of 133020525131267 is 762131525020331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133020525131267 is a prime.
It is a super-3 number, since 3×1330205251312673 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (133020525131297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510262565633 + 66510262565634.
It is an arithmetic number, because the mean of its divisors is an integer number (66510262565634).
Almost surely, 2133020525131267 is an apocalyptic number.
133020525131267 is a deficient number, since it is larger than the sum of its proper divisors (1).
133020525131267 is an equidigital number, since it uses as much as digits as its factorization.
133020525131267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 41.
The spelling of 133020525131267 in words is "one hundred thirty-three trillion, twenty billion, five hundred twenty-five million, one hundred thirty-one thousand, two hundred sixty-seven".
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