Base | Representation |
---|---|
bin | 11110001111101101101001… |
… | …111111101101100111100011 |
3 | 122102222200222212110020210021 |
4 | 132033231221333231213203 |
5 | 114413404414332342034 |
6 | 1150525033410414311 |
7 | 40006315412525605 |
oct | 3617555177554743 |
9 | 572880885406707 |
10 | 133021210434019 |
11 | 39425a84485a16 |
12 | 12b0449a291397 |
13 | 592bb0049845b |
14 | 24bc392025175 |
15 | 105a2c0e556b4 |
hex | 78fb69fed9e3 |
133021210434019 has 2 divisors, whose sum is σ = 133021210434020. Its totient is φ = 133021210434018.
The previous prime is 133021210433999. The next prime is 133021210434023. The reversal of 133021210434019 is 910434012120331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133021210434019 - 211 = 133021210431971 is a prime.
It is a super-2 number, since 2×1330212104340192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133021210437019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510605217009 + 66510605217010.
It is an arithmetic number, because the mean of its divisors is an integer number (66510605217010).
Almost surely, 2133021210434019 is an apocalyptic number.
133021210434019 is a deficient number, since it is larger than the sum of its proper divisors (1).
133021210434019 is an equidigital number, since it uses as much as digits as its factorization.
133021210434019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 133021210434019 in words is "one hundred thirty-three trillion, twenty-one billion, two hundred ten million, four hundred thirty-four thousand, nineteen".
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