Base | Representation |
---|---|
bin | 1100000110010010010001… |
… | …0100010100011010111011 |
3 | 1202002200002211021020201110 |
4 | 3001210210110110122323 |
5 | 3220420221443201021 |
6 | 44142524433251403 |
7 | 2542022003044425 |
oct | 301444424243273 |
9 | 52080084236643 |
10 | 13302123022011 |
11 | 426944272993a |
12 | 15aa05a103b63 |
13 | 7565005a5965 |
14 | 33db7d0c7815 |
15 | 181043409476 |
hex | c19245146bb |
13302123022011 has 4 divisors (see below), whose sum is σ = 17736164029352. Its totient is φ = 8868082014672.
The previous prime is 13302123022009. The next prime is 13302123022043. The reversal of 13302123022011 is 11022032120331.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13302123022011 - 21 = 13302123022009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13302123022211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2217020503666 + ... + 2217020503671.
It is an arithmetic number, because the mean of its divisors is an integer number (4434041007338).
Almost surely, 213302123022011 is an apocalyptic number.
13302123022011 is a deficient number, since it is larger than the sum of its proper divisors (4434041007341).
13302123022011 is an equidigital number, since it uses as much as digits as its factorization.
13302123022011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4434041007340.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13302123022011 its reverse (11022032120331), we get a palindrome (24324155142342).
The spelling of 13302123022011 in words is "thirteen trillion, three hundred two billion, one hundred twenty-three million, twenty-two thousand, eleven".
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