13302140042041 has 2 divisors, whose sum is σ = 13302140042042. Its totient is φ = 13302140042040.

The previous prime is 13302140042027. The next prime is 13302140042053. The reversal of 13302140042041 is 14024004120331.

13302140042041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11238619284025 + 2063520758016 = 3352405^2 + 1436496^2 .

It is a cyclic number.

It is not a de Polignac number, because 13302140042041 - 2²⁷ = 13302005824313 is a prime.

It is a super-3 number, since 3×13302140042041³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13302140041997 and 13302140042015.

It is not a weakly prime, because it can be changed into another prime (13302140042141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651070021020 + 6651070021021.

It is an arithmetic number, because the mean of its divisors is an integer number (6651070021021).

Almost surely, 2^{13302140042041} is an apocalyptic number.

It is an amenable number.

13302140042041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13302140042041 is an equidigital number, since it uses as much as digits as its factorization.

13302140042041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13302140042041 its reverse (14024004120331), we get a palindrome (27326144162372).

The spelling of 13302140042041 in words is "thirteen trillion, three hundred two billion, one hundred forty million, forty-two thousand, forty-one".