Base | Representation |
---|---|
bin | 10011010110110111111… |
… | …000110100100000010010 |
3 | 11201011120000110120212202 |
4 | 103112313320310200102 |
5 | 133243302341120424 |
6 | 2455033233523202 |
7 | 165051224415662 |
oct | 23266770644022 |
9 | 4634500416782 |
10 | 1330230020114 |
11 | 473169192796 |
12 | 195983413502 |
13 | 985950279c8 |
14 | 4855238c1a2 |
15 | 24907d382ae |
hex | 135b7e34812 |
1330230020114 has 4 divisors (see below), whose sum is σ = 1995345030174. Its totient is φ = 665115010056.
The previous prime is 1330230020101. The next prime is 1330230020131. The reversal of 1330230020114 is 4110200320331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1330204689025 + 25331089 = 1153345^2 + 5033^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332557505027 + ... + 332557505030.
Almost surely, 21330230020114 is an apocalyptic number.
1330230020114 is a deficient number, since it is larger than the sum of its proper divisors (665115010060).
1330230020114 is an equidigital number, since it uses as much as digits as its factorization.
1330230020114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665115010059.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1330230020114 its reverse (4110200320331), we get a palindrome (5440430340445).
The spelling of 1330230020114 in words is "one trillion, three hundred thirty billion, two hundred thirty million, twenty thousand, one hundred fourteen".
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