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133023012426169 is a prime number
BaseRepresentation
bin11110001111101111010101…
…011001110001000110111001
3122102222212122110012221022021
4132033233111121301012321
5114413422112140114134
61150525532301354441
740006411153311205
oct3617572531610671
9572885573187267
10133023012426169
1139426819680328
1212b04901868a21
13592c0299051b8
1424bc4c3499b05
15105a3792540b4
hex78fbd56711b9

133023012426169 has 2 divisors, whose sum is σ = 133023012426170. Its totient is φ = 133023012426168.

The previous prime is 133023012426131. The next prime is 133023012426193. The reversal of 133023012426169 is 961624210320331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94067439152569 + 38955573273600 = 9698837^2 + 6241440^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133023012426169 is a prime.

It is a super-3 number, since 3×1330230124261693 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (133023012426119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511506213084 + 66511506213085.

It is an arithmetic number, because the mean of its divisors is an integer number (66511506213085).

Almost surely, 2133023012426169 is an apocalyptic number.

It is an amenable number.

133023012426169 is a deficient number, since it is larger than the sum of its proper divisors (1).

133023012426169 is an equidigital number, since it uses as much as digits as its factorization.

133023012426169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 43.

The spelling of 133023012426169 in words is "one hundred thirty-three trillion, twenty-three billion, twelve million, four hundred twenty-six thousand, one hundred sixty-nine".