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13302313345353 = 34434104448451
BaseRepresentation
bin1100000110010010111110…
…1010010110000101001001
31202002200121002101200021010
43001210233222112011021
53220421114204022403
644142555352434133
72542026503550114
oct301445752260511
952080532350233
1013302313345353
11426953010265a
1215aa0b19a8949
13756530b52616
1433db9a4ab57b
15181054ea1603
hexc192fa96149

13302313345353 has 4 divisors (see below), whose sum is σ = 17736417793808. Its totient is φ = 8868208896900.

The previous prime is 13302313345291. The next prime is 13302313345367. The reversal of 13302313345353 is 35354331320331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13302313345353 - 210 = 13302313344329 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13302313305353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2217052224223 + ... + 2217052224228.

It is an arithmetic number, because the mean of its divisors is an integer number (4434104448452).

Almost surely, 213302313345353 is an apocalyptic number.

It is an amenable number.

13302313345353 is a deficient number, since it is larger than the sum of its proper divisors (4434104448455).

13302313345353 is an equidigital number, since it uses as much as digits as its factorization.

13302313345353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4434104448454.

The product of its (nonzero) digits is 437400, while the sum is 39.

Adding to 13302313345353 its reverse (35354331320331), we get a palindrome (48656644665684).

The spelling of 13302313345353 in words is "thirteen trillion, three hundred two billion, three hundred thirteen million, three hundred forty-five thousand, three hundred fifty-three".

Divisors: 1 3 4434104448451 13302313345353