Base | Representation |
---|---|
bin | 11110001111101111011101… |
… | …100110110110101111100011 |
3 | 122102222220000001020012210121 |
4 | 132033233131212312233203 |
5 | 114413422402404343401 |
6 | 1150525554055541111 |
7 | 40006414444306261 |
oct | 3617573546665743 |
9 | 572886001205717 |
10 | 133023150074851 |
11 | 3942688a346873 |
12 | 12b0493b98a797 |
13 | 592c04c29b21a |
14 | 24bc4d788b431 |
15 | 105a386393ca1 |
hex | 78fbdd9b6be3 |
133023150074851 has 2 divisors, whose sum is σ = 133023150074852. Its totient is φ = 133023150074850.
The previous prime is 133023150074833. The next prime is 133023150074861. The reversal of 133023150074851 is 158470051320331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133023150074851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133023150074798 and 133023150074807.
It is not a weakly prime, because it can be changed into another prime (133023150074861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511575037425 + 66511575037426.
It is an arithmetic number, because the mean of its divisors is an integer number (66511575037426).
Almost surely, 2133023150074851 is an apocalyptic number.
133023150074851 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023150074851 is an equidigital number, since it uses as much as digits as its factorization.
133023150074851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 133023150074851 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred fifty million, seventy-four thousand, eight hundred fifty-one".
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