Base | Representation |
---|---|
bin | 11110001111101111101001… |
… | …001111111101100011000011 |
3 | 122102222220111122202202112111 |
4 | 132033233221033331203003 |
5 | 114413423302410300003 |
6 | 1150530025314240151 |
7 | 40006422335453332 |
oct | 3617575117754303 |
9 | 572886448682474 |
10 | 133023345400003 |
11 | 3942697a626513 |
12 | 12b04995286057 |
13 | 592c0808a9736 |
14 | 24bc5157b3d19 |
15 | 105a3985c7e6d |
hex | 78fbe93fd8c3 |
133023345400003 has 2 divisors, whose sum is σ = 133023345400004. Its totient is φ = 133023345400002.
The previous prime is 133023345399983. The next prime is 133023345400019. The reversal of 133023345400003 is 300004543320331.
It is a strong prime.
It is an emirp because it is prime and its reverse (300004543320331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133023345400003 - 29 = 133023345399491 is a prime.
It is not a weakly prime, because it can be changed into another prime (133023345400093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511672700001 + 66511672700002.
It is an arithmetic number, because the mean of its divisors is an integer number (66511672700002).
Almost surely, 2133023345400003 is an apocalyptic number.
133023345400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023345400003 is an equidigital number, since it uses as much as digits as its factorization.
133023345400003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 31.
Adding to 133023345400003 its reverse (300004543320331), we get a palindrome (433027888720334).
The spelling of 133023345400003 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred forty-five million, four hundred thousand, three".
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