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13302421404443 = 44156330125761
BaseRepresentation
bin1100000110010011011000…
…0110100011101100011011
31202002200212121201122110122
43001210312012203230123
53220421324334420233
644143014212503455
72542032255206153
oct301446606435433
952080777648418
1013302421404443
1142695860a8a96
1215aa12201ab8b
1375654a358402
1433dbaa999763
1518105e6e8d98
hexc19361a3b1b

13302421404443 has 4 divisors (see below), whose sum is σ = 13302451971768. Its totient is φ = 13302390837120.

The previous prime is 13302421404439. The next prime is 13302421404499. The reversal of 13302421404443 is 34440412420331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13302421404443 - 22 = 13302421404439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13302421404413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14621318 + ... + 15504443.

It is an arithmetic number, because the mean of its divisors is an integer number (3325612992942).

Almost surely, 213302421404443 is an apocalyptic number.

13302421404443 is a deficient number, since it is larger than the sum of its proper divisors (30567325).

13302421404443 is an equidigital number, since it uses as much as digits as its factorization.

13302421404443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30567324.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 13302421404443 its reverse (34440412420331), we get a palindrome (47742833824774).

The spelling of 13302421404443 in words is "thirteen trillion, three hundred two billion, four hundred twenty-one million, four hundred four thousand, four hundred forty-three".

Divisors: 1 441563 30125761 13302421404443