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1330250142121 is a prime number
BaseRepresentation
bin10011010110111001000…
…101100101000110101001
311201011121102022220002021
4103112321011211012221
5133243323014021441
62455035233104441
7165051560433505
oct23267105450651
94634542286067
101330250142121
1147317958674a
1219598a0b8121
1398599251814
1448554d09305
15249099b03d1
hex135b91651a9

1330250142121 has 2 divisors, whose sum is σ = 1330250142122. Its totient is φ = 1330250142120.

The previous prime is 1330250142083. The next prime is 1330250142167. The reversal of 1330250142121 is 1212410520331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1330248516496 + 1625625 = 1153364^2 + 1275^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330250142121 - 213 = 1330250133929 is a prime.

It is a super-2 number, since 2×13302501421212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1330250142181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665125071060 + 665125071061.

It is an arithmetic number, because the mean of its divisors is an integer number (665125071061).

Almost surely, 21330250142121 is an apocalyptic number.

It is an amenable number.

1330250142121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330250142121 is an equidigital number, since it uses as much as digits as its factorization.

1330250142121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1330250142121 its reverse (1212410520331), we get a palindrome (2542660662452).

The spelling of 1330250142121 in words is "one trillion, three hundred thirty billion, two hundred fifty million, one hundred forty-two thousand, one hundred twenty-one".