133025350061041 has 4 divisors (see below), whose sum is σ = 140026684274800. Its totient is φ = 126024015847284.

The previous prime is 133025350061029. The next prime is 133025350061119. The reversal of 133025350061041 is 140160053520331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133025350061041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133025350060988 and 133025350061006.

It is not an unprimeable number, because it can be changed into a prime (133025350061441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3500667106851 + ... + 3500667106888.

It is an arithmetic number, because the mean of its divisors is an integer number (35006671068700).

Almost surely, 2^{133025350061041} is an apocalyptic number.

It is an amenable number.

133025350061041 is a deficient number, since it is larger than the sum of its proper divisors (7001334213759).

133025350061041 is an equidigital number, since it uses as much as digits as its factorization.

133025350061041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7001334213758.

The product of its (nonzero) digits is 32400, while the sum is 34.

The spelling of 133025350061041 in words is "one hundred thirty-three trillion, twenty-five billion, three hundred fifty million, sixty-one thousand, forty-one".