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133030033242131 is a prime number
BaseRepresentation
bin11110001111110101110111…
…111000000011100000010011
3122110000112202202010100020002
4132033311313320003200103
5114414031002002222011
61150533053102040215
740010050144255334
oct3617656770034023
9573015682110202
10133030033242131
11394297a1752273
1212b06140b7906b
13592c8a8318a7c
1424bc98bab428b
15105a63a7d0c3b
hex78fd77e03813

133030033242131 has 2 divisors, whose sum is σ = 133030033242132. Its totient is φ = 133030033242130.

The previous prime is 133030033242121. The next prime is 133030033242143. The reversal of 133030033242131 is 131242330030331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133030033242131 is a prime.

It is a super-2 number, since 2×1330300332421312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133030033242094 and 133030033242103.

It is not a weakly prime, because it can be changed into another prime (133030033242121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515016621065 + 66515016621066.

It is an arithmetic number, because the mean of its divisors is an integer number (66515016621066).

Almost surely, 2133030033242131 is an apocalyptic number.

133030033242131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133030033242131 is an equidigital number, since it uses as much as digits as its factorization.

133030033242131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 133030033242131 its reverse (131242330030331), we get a palindrome (264272363272462).

The spelling of 133030033242131 in words is "one hundred thirty-three trillion, thirty billion, thirty-three million, two hundred forty-two thousand, one hundred thirty-one".