Base | Representation |
---|---|
bin | 11110001111110110111001… |
… | …111111101010111111100111 |
3 | 122110000122122001110021011110 |
4 | 132033312321333222333213 |
5 | 114414040234442111033 |
6 | 1150533355130040103 |
7 | 40010116504144626 |
oct | 3617667177527747 |
9 | 573018561407143 |
10 | 133031142535143 |
11 | 3942a210934556 |
12 | 12b063b0579033 |
13 | 592ca240a1578 |
14 | 24bca551516bd |
15 | 105a6a2da0363 |
hex | 78fdb9feafe7 |
133031142535143 has 32 divisors (see below), whose sum is σ = 195055378882560. Its totient is φ = 80329726170720.
The previous prime is 133031142535103. The next prime is 133031142535157. The reversal of 133031142535143 is 341535241130331.
It is not a de Polignac number, because 133031142535143 - 225 = 133031108980711 is a prime.
It is a super-3 number, since 3×1330311425351433 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133031142535103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 453386121 + ... + 453679442.
It is an arithmetic number, because the mean of its divisors is an integer number (6095480590080).
Almost surely, 2133031142535143 is an apocalyptic number.
133031142535143 is a deficient number, since it is larger than the sum of its proper divisors (62024236347417).
133031142535143 is a wasteful number, since it uses less digits than its factorization.
133031142535143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 907065699.
The product of its (nonzero) digits is 194400, while the sum is 39.
Adding to 133031142535143 its reverse (341535241130331), we get a palindrome (474566383665474).
The spelling of 133031142535143 in words is "one hundred thirty-three trillion, thirty-one billion, one hundred forty-two million, five hundred thirty-five thousand, one hundred forty-three".
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