Base | Representation |
---|---|
bin | 10011010110111100110… |
… | …010110010000101101001 |
3 | 11201011202202100000210211 |
4 | 103112330302302011221 |
5 | 133243434423322213 |
6 | 2455045333541121 |
7 | 165053244114232 |
oct | 23267462620551 |
9 | 4634682300724 |
10 | 1330312323433 |
11 | 473200697465 |
12 | 1959a6aa47a1 |
13 | 985a90b35b2 |
14 | 4855d294089 |
15 | 2491019453d |
hex | 135bccb2169 |
1330312323433 has 2 divisors, whose sum is σ = 1330312323434. Its totient is φ = 1330312323432.
The previous prime is 1330312323407. The next prime is 1330312323449. The reversal of 1330312323433 is 3343232130331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1123203594969 + 207108728464 = 1059813^2 + 455092^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330312323433 - 29 = 1330312322921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330312323395 and 1330312323404.
It is not a weakly prime, because it can be changed into another prime (1330312323493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665156161716 + 665156161717.
It is an arithmetic number, because the mean of its divisors is an integer number (665156161717).
Almost surely, 21330312323433 is an apocalyptic number.
It is an amenable number.
1330312323433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330312323433 is an equidigital number, since it uses as much as digits as its factorization.
1330312323433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 31.
Adding to 1330312323433 its reverse (3343232130331), we get a palindrome (4673544453764).
The spelling of 1330312323433 in words is "one trillion, three hundred thirty billion, three hundred twelve million, three hundred twenty-three thousand, four hundred thirty-three".
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