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133031524897 is a prime number
BaseRepresentation
bin111101111100101001…
…0111111101000100001
3110201101012021122222201
41323321102333220201
54134422032244042
6141040331133201
712416434206235
oct1737122775041
9421335248881
10133031524897
1151466911707
1221947ba4201
13c710c7614b
14661dd5a5c5
1536d90831b7
hex1ef94bfa21

133031524897 has 2 divisors, whose sum is σ = 133031524898. Its totient is φ = 133031524896.

The previous prime is 133031524883. The next prime is 133031525131. The reversal of 133031524897 is 798425130331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92269530081 + 40761994816 = 303759^2 + 201896^2 .

It is a cyclic number.

It is not a de Polignac number, because 133031524897 - 215 = 133031492129 is a prime.

It is a super-2 number, since 2×1330315248972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133031524807) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515762448 + 66515762449.

It is an arithmetic number, because the mean of its divisors is an integer number (66515762449).

Almost surely, 2133031524897 is an apocalyptic number.

It is an amenable number.

133031524897 is a deficient number, since it is larger than the sum of its proper divisors (1).

133031524897 is an equidigital number, since it uses as much as digits as its factorization.

133031524897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 46.

The spelling of 133031524897 in words is "one hundred thirty-three billion, thirty-one million, five hundred twenty-four thousand, eight hundred ninety-seven".