1330323212041 has 4 divisors (see below), whose sum is σ = 1330392278032. Its totient is φ = 1330254146052.

The previous prime is 1330323212027. The next prime is 1330323212083. The reversal of 1330323212041 is 1402123230331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330323212041 - 2¹⁷ = 1330323080969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330323211997 and 1330323212015.

It is not an unprimeable number, because it can be changed into a prime (1330323212011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34504095 + ... + 34542628.

It is an arithmetic number, because the mean of its divisors is an integer number (332598069508).

Almost surely, 2^{1330323212041} is an apocalyptic number.

It is an amenable number.

1330323212041 is a deficient number, since it is larger than the sum of its proper divisors (69065991).

1330323212041 is an equidigital number, since it uses as much as digits as its factorization.

1330323212041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69065990.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1330323212041 its reverse (1402123230331), we get a palindrome (2732446442372).

The spelling of 1330323212041 in words is "one trillion, three hundred thirty billion, three hundred twenty-three million, two hundred twelve thousand, forty-one".