Base | Representation |
---|---|
bin | 11110001111111000000111… |
… | …011010100101000011010011 |
3 | 122110000202222120120011212111 |
4 | 132033320013122211003103 |
5 | 114414100420001344243 |
6 | 1150534132050010151 |
7 | 40010163625461664 |
oct | 3617700732450323 |
9 | 573022876504774 |
10 | 133032441434323 |
11 | 3942a81804a752 |
12 | 12b066b3576957 |
13 | 592cba0212472 |
14 | 24bcb3986736b |
15 | 105a72be2439d |
hex | 78fe076a50d3 |
133032441434323 has 2 divisors, whose sum is σ = 133032441434324. Its totient is φ = 133032441434322.
The previous prime is 133032441434273. The next prime is 133032441434357. The reversal of 133032441434323 is 323434144230331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133032441434323 is a prime.
It is not a weakly prime, because it can be changed into another prime (133032441434023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66516220717161 + 66516220717162.
It is an arithmetic number, because the mean of its divisors is an integer number (66516220717162).
Almost surely, 2133032441434323 is an apocalyptic number.
133032441434323 is a deficient number, since it is larger than the sum of its proper divisors (1).
133032441434323 is an equidigital number, since it uses as much as digits as its factorization.
133032441434323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 40.
Adding to 133032441434323 its reverse (323434144230331), we get a palindrome (456466585664654).
The spelling of 133032441434323 in words is "one hundred thirty-three trillion, thirty-two billion, four hundred forty-one million, four hundred thirty-four thousand, three hundred twenty-three".
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