Base | Representation |
---|---|
bin | 10011010110111110011… |
… | …101111110011001000010 |
3 | 11201011211201012122111012 |
4 | 103112332131332121002 |
5 | 133244014122020414 |
6 | 2455052220120522 |
7 | 165054035006654 |
oct | 23267635763102 |
9 | 4634751178435 |
10 | 1330340423234 |
11 | 47321553a239 |
12 | 1959b4396142 |
13 | 985b1b716b4 |
14 | 48562cca6d4 |
15 | 2491289533e |
hex | 135be77e642 |
1330340423234 has 4 divisors (see below), whose sum is σ = 1995510634854. Its totient is φ = 665170211616.
The previous prime is 1330340423183. The next prime is 1330340423281. The reversal of 1330340423234 is 4323240430331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1281276844225 + 49063579009 = 1131935^2 + 221503^2 .
It is a super-3 number, since 3×13303404232343 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1330340423234.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332585105807 + ... + 332585105810.
Almost surely, 21330340423234 is an apocalyptic number.
1330340423234 is a deficient number, since it is larger than the sum of its proper divisors (665170211620).
1330340423234 is an equidigital number, since it uses as much as digits as its factorization.
1330340423234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665170211619.
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 1330340423234 its reverse (4323240430331), we get a palindrome (5653580853565).
The spelling of 1330340423234 in words is "one trillion, three hundred thirty billion, three hundred forty million, four hundred twenty-three thousand, two hundred thirty-four".
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