Base | Representation |
---|---|
bin | 10011010110111111010… |
… | …111100010010001111001 |
3 | 11201011212202121020222201 |
4 | 103112333113202101321 |
5 | 133244032002344231 |
6 | 2455053515350201 |
7 | 165054310163554 |
oct | 23267727422171 |
9 | 4634782536881 |
10 | 1330355512441 |
11 | 473223005a5a |
12 | 1959b9452361 |
13 | 985b5025817 |
14 | 48564cd769b |
15 | 24913d76161 |
hex | 135bf5e2479 |
1330355512441 has 4 divisors (see below), whose sum is σ = 1330359129472. Its totient is φ = 1330351895412.
The previous prime is 1330355512403. The next prime is 1330355512487. The reversal of 1330355512441 is 1442155530331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1330355512441 - 29 = 1330355511929 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1330355512441.
It is not an unprimeable number, because it can be changed into a prime (1330355212441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1185201 + ... + 2016286.
It is an arithmetic number, because the mean of its divisors is an integer number (332589782368).
Almost surely, 21330355512441 is an apocalyptic number.
It is an amenable number.
1330355512441 is a deficient number, since it is larger than the sum of its proper divisors (3617031).
1330355512441 is an equidigital number, since it uses as much as digits as its factorization.
1330355512441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3617030.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 1330355512441 in words is "one trillion, three hundred thirty billion, three hundred fifty-five million, five hundred twelve thousand, four hundred forty-one".
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