Base | Representation |
---|---|
bin | 10011010111000010001… |
… | …000111011010100000011 |
3 | 11201012000000002210202222 |
4 | 103113002020323110003 |
5 | 133244130403430332 |
6 | 2455102300201255 |
7 | 165055413352151 |
oct | 23270210732403 |
9 | 4635000083688 |
10 | 1330402014467 |
11 | 473247287689 |
12 | 195a10b3922b |
13 | 985c1857a06 |
14 | 4856b1603d1 |
15 | 24917eae712 |
hex | 135c223b503 |
1330402014467 has 2 divisors, whose sum is σ = 1330402014468. Its totient is φ = 1330402014466.
The previous prime is 1330402014413. The next prime is 1330402014497. The reversal of 1330402014467 is 7644102040331.
It is a strong prime.
It is an emirp because it is prime and its reverse (7644102040331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1330402014467 - 28 = 1330402014211 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330402014497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665201007233 + 665201007234.
It is an arithmetic number, because the mean of its divisors is an integer number (665201007234).
Almost surely, 21330402014467 is an apocalyptic number.
1330402014467 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330402014467 is an equidigital number, since it uses as much as digits as its factorization.
1330402014467 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 1330402014467 its reverse (7644102040331), we get a palindrome (8974504054798).
The spelling of 1330402014467 in words is "one trillion, three hundred thirty billion, four hundred two million, fourteen thousand, four hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •