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13304145034 = 26652072517
BaseRepresentation
bin11000110001111110…
…10010010010001010
31021100012002121000101
430120333102102022
5204221330120114
610040054000014
7650455236565
oct143077222212
937305077011
1013304145034
115707930094
1226b364600a
1313403c138b
14902cdb4dc
1552cecdd74
hex318fd248a

13304145034 has 4 divisors (see below), whose sum is σ = 19956217554. Its totient is φ = 6652072516.

The previous prime is 13304145031. The next prime is 13304145077. The reversal of 13304145034 is 43054140331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11042857225 + 2261287809 = 105085^2 + 47553^2 .

It is a super-2 number, since 2×133041450342 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13304144993 and 13304145011.

It is not an unprimeable number, because it can be changed into a prime (13304145031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3326036257 + ... + 3326036260.

Almost surely, 213304145034 is an apocalyptic number.

13304145034 is a deficient number, since it is larger than the sum of its proper divisors (6652072520).

13304145034 is an equidigital number, since it uses as much as digits as its factorization.

13304145034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6652072519.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13304145034 its reverse (43054140331), we get a palindrome (56358285365).

The spelling of 13304145034 in words is "thirteen billion, three hundred four million, one hundred forty-five thousand, thirty-four".

Divisors: 1 2 6652072517 13304145034