Base | Representation |
---|---|
bin | 11110010000000001111110… |
… | …110010100011001000111010 |
3 | 122110001210022210121110000222 |
4 | 132100001332302203020322 |
5 | 114414234113220004432 |
6 | 1150543043124300042 |
7 | 40011020261136311 |
oct | 3620017662431072 |
9 | 573053283543028 |
10 | 133043034141242 |
11 | 39434263391195 |
12 | 12b0876ab41622 |
13 | 5930b9a943a94 |
14 | 24bd4625d5278 |
15 | 105ab4bd5e112 |
hex | 79007eca323a |
133043034141242 has 8 divisors (see below), whose sum is σ = 199573759256916. Its totient is φ = 66518447722272.
The previous prime is 133043034141211. The next prime is 133043034141323. The reversal of 133043034141242 is 242141430340331.
133043034141242 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 93687474034441 + 39355560106801 = 9679229^2 + 6273401^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1534619993 + ... + 1534706684.
Almost surely, 2133043034141242 is an apocalyptic number.
133043034141242 is a deficient number, since it is larger than the sum of its proper divisors (66530725115674).
133043034141242 is a wasteful number, since it uses less digits than its factorization.
133043034141242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3069348352.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 133043034141242 its reverse (242141430340331), we get a palindrome (375184464481573).
The spelling of 133043034141242 in words is "one hundred thirty-three trillion, forty-three billion, thirty-four million, one hundred forty-one thousand, two hundred forty-two".
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