Base | Representation |
---|---|
bin | 1100000110011010011011… |
… | …1010101010000111000001 |
3 | 1202002212202112012001221022 |
4 | 3001212212322222013001 |
5 | 3220434213403013101 |
6 | 44143530104035225 |
7 | 2542130210016266 |
oct | 301464672520701 |
9 | 52085675161838 |
10 | 13304314110401 |
11 | 426a367521a96 |
12 | 15aa56ba62b15 |
13 | 75678c506c72 |
14 | 33dd0a0c526d |
15 | 181120965a1b |
hex | c19a6eaa1c1 |
13304314110401 has 2 divisors, whose sum is σ = 13304314110402. Its totient is φ = 13304314110400.
The previous prime is 13304314110371. The next prime is 13304314110449. The reversal of 13304314110401 is 10401141340331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12877906416400 + 426407694001 = 3588580^2 + 652999^2 .
It is a cyclic number.
It is not a de Polignac number, because 13304314110401 - 26 = 13304314110337 is a prime.
It is not a weakly prime, because it can be changed into another prime (13304314110481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652157055200 + 6652157055201.
It is an arithmetic number, because the mean of its divisors is an integer number (6652157055201).
Almost surely, 213304314110401 is an apocalyptic number.
It is an amenable number.
13304314110401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304314110401 is an equidigital number, since it uses as much as digits as its factorization.
13304314110401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 13304314110401 its reverse (10401141340331), we get a palindrome (23705455450732).
The spelling of 13304314110401 in words is "thirteen trillion, three hundred four billion, three hundred fourteen million, one hundred ten thousand, four hundred one".
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