Base | Representation |
---|---|
bin | 11110010000000010001110… |
… | …111000001011111100011001 |
3 | 122110001211000121111110111021 |
4 | 132100002032320023330121 |
5 | 114414240141314221203 |
6 | 1150543130005402441 |
7 | 40011030046306504 |
oct | 3620021670137431 |
9 | 573054017443437 |
10 | 133043304054553 |
11 | 39434391786042 |
12 | 12b08825409421 |
13 | 5930c118392b9 |
14 | 24bd48a3b613b |
15 | 105ab658c85bd |
hex | 79008ee0bf19 |
133043304054553 has 8 divisors (see below), whose sum is σ = 133545953776320. Its totient is φ = 132540714073680.
The previous prime is 133043304054509. The next prime is 133043304054589. The reversal of 133043304054553 is 355450403340331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133043304054553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133043301054553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10470283 + ... + 19383328.
It is an arithmetic number, because the mean of its divisors is an integer number (16693244222040).
Almost surely, 2133043304054553 is an apocalyptic number.
It is an amenable number.
133043304054553 is a deficient number, since it is larger than the sum of its proper divisors (502649721767).
133043304054553 is a wasteful number, since it uses less digits than its factorization.
133043304054553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29870447.
The product of its (nonzero) digits is 1944000, while the sum is 43.
Adding to 133043304054553 its reverse (355450403340331), we get a palindrome (488493707394884).
The spelling of 133043304054553 in words is "one hundred thirty-three trillion, forty-three billion, three hundred four million, fifty-four thousand, five hundred fifty-three".
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