Base | Representation |
---|---|
bin | 1100000110011010011111… |
… | …1111101111101010101001 |
3 | 1202002212210210021012010211 |
4 | 3001212213333233222221 |
5 | 3220434233022033342 |
6 | 44143531552141121 |
7 | 2542130516656201 |
oct | 301464777575251 |
9 | 52085723235124 |
10 | 13304332221097 |
11 | 426a376771905 |
12 | 15aa575b377a1 |
13 | 7567931a8458 |
14 | 33dd0c67b401 |
15 | 181122341c17 |
hex | c19a7fefaa9 |
13304332221097 has 2 divisors, whose sum is σ = 13304332221098. Its totient is φ = 13304332221096.
The previous prime is 13304332221041. The next prime is 13304332221109. The reversal of 13304332221097 is 79012223340331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13082826446361 + 221505774736 = 3617019^2 + 470644^2 .
It is a cyclic number.
It is not a de Polignac number, because 13304332221097 - 231 = 13302184737449 is a prime.
It is not a weakly prime, because it can be changed into another prime (13304332221497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652166110548 + 6652166110549.
It is an arithmetic number, because the mean of its divisors is an integer number (6652166110549).
Almost surely, 213304332221097 is an apocalyptic number.
It is an amenable number.
13304332221097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13304332221097 is an equidigital number, since it uses as much as digits as its factorization.
13304332221097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 163296, while the sum is 40.
The spelling of 13304332221097 in words is "thirteen trillion, three hundred four billion, three hundred thirty-two million, two hundred twenty-one thousand, ninety-seven".
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