1330434050042 has 4 divisors (see below), whose sum is σ = 1995651075066. Its totient is φ = 665217025020.

The previous prime is 1330434050021. The next prime is 1330434050081. The reversal of 1330434050042 is 2400504340331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 909221367961 + 421212682081 = 953531^2 + 649009^2 .

It is a super-2 number, since 2×1330434050042² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330434049987 and 1330434050014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332608512509 + ... + 332608512512.

Almost surely, 2^{1330434050042} is an apocalyptic number.

1330434050042 is a deficient number, since it is larger than the sum of its proper divisors (665217025024).

1330434050042 is an equidigital number, since it uses as much as digits as its factorization.

1330434050042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 665217025023.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 1330434050042 its reverse (2400504340331), we get a palindrome (3730938390373).

The spelling of 1330434050042 in words is "one trillion, three hundred thirty billion, four hundred thirty-four million, fifty thousand, forty-two".