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133044012240001 is a prime number
BaseRepresentation
bin11110010000000010111001…
…000101101100110010000001
3122110001212211222002000021221
4132100002321011230302001
5114414243114113140001
61150543324144315041
740011053435632222
oct3620027105546201
9573055758060257
10133044012240001
1139434715506275
1212b089a2612a81
135930cc5483345
1424bd516481249
15105aba7b661a1
hex7900b916cc81

133044012240001 has 2 divisors, whose sum is σ = 133044012240002. Its totient is φ = 133044012240000.

The previous prime is 133044012239981. The next prime is 133044012240017. The reversal of 133044012240001 is 100042210440331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110156590793601 + 22887421446400 = 10495551^2 + 4784080^2 .

It is a cyclic number.

It is not a de Polignac number, because 133044012240001 - 239 = 132494256426113 is a prime.

It is not a weakly prime, because it can be changed into another prime (133044012240301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66522006120000 + 66522006120001.

It is an arithmetic number, because the mean of its divisors is an integer number (66522006120001).

Almost surely, 2133044012240001 is an apocalyptic number.

It is an amenable number.

133044012240001 is a deficient number, since it is larger than the sum of its proper divisors (1).

133044012240001 is an equidigital number, since it uses as much as digits as its factorization.

133044012240001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 133044012240001 its reverse (100042210440331), we get a palindrome (233086222680332).

The spelling of 133044012240001 in words is "one hundred thirty-three trillion, forty-four billion, twelve million, two hundred forty thousand, one".