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133044101224033 is a prime number
BaseRepresentation
bin11110010000000010111110…
…011001001001011001100001
3122110001220002011111212102211
4132100002332121021121201
5114414243304403132113
61150543341043442121
740011055566163666
oct3620027631113141
9573056064455384
10133044101224033
113943476076329a
1212b08a08386341
13593100aa3aa0c
1424bd524205a6d
15105abb0891b3d
hex7900be649661

133044101224033 has 2 divisors, whose sum is σ = 133044101224034. Its totient is φ = 133044101224032.

The previous prime is 133044101223911. The next prime is 133044101224039. The reversal of 133044101224033 is 330422101440331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90383961674304 + 42660139549729 = 9507048^2 + 6531473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133044101224033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133044101223986 and 133044101224004.

It is not a weakly prime, because it can be changed into another prime (133044101224039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66522050612016 + 66522050612017.

It is an arithmetic number, because the mean of its divisors is an integer number (66522050612017).

Almost surely, 2133044101224033 is an apocalyptic number.

It is an amenable number.

133044101224033 is a deficient number, since it is larger than the sum of its proper divisors (1).

133044101224033 is an equidigital number, since it uses as much as digits as its factorization.

133044101224033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 133044101224033 its reverse (330422101440331), we get a palindrome (463466202664364).

The spelling of 133044101224033 in words is "one hundred thirty-three trillion, forty-four billion, one hundred one million, two hundred twenty-four thousand, thirty-three".