Base | Representation |
---|---|
bin | 1100000110011011101010… |
… | …1001000100011100101011 |
3 | 1202002220121120220020111200 |
4 | 3001212322221010130223 |
5 | 3220440403112402021 |
6 | 44144023005055243 |
7 | 2542141335633306 |
oct | 301467251043453 |
9 | 52086546806450 |
10 | 13304645044011 |
11 | 426a517304342 |
12 | 15aa642857523 |
13 | 756812c45979 |
14 | 33dd3c02bb3d |
15 | 18113ea35126 |
hex | c19baa4472b |
13304645044011 has 12 divisors (see below), whose sum is σ = 19218513090192. Its totient is φ = 8869443760656.
The previous prime is 13304645043979. The next prime is 13304645044027. The reversal of 13304645044011 is 11044054640331.
13304645044011 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 4 + 645 + 0 + 4 + 4 + 0 + 1 + 1 = 666.
It is not a de Polignac number, because 13304645044011 - 25 = 13304645043979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13304645444011) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26369716 + ... + 26869521.
It is an arithmetic number, because the mean of its divisors is an integer number (1601542757516).
Almost surely, 213304645044011 is an apocalyptic number.
13304645044011 is a deficient number, since it is larger than the sum of its proper divisors (5913868046181).
13304645044011 is a wasteful number, since it uses less digits than its factorization.
13304645044011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53267010 (or 53267007 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 36.
Adding to 13304645044011 its reverse (11044054640331), we get a palindrome (24348699684342).
The spelling of 13304645044011 in words is "thirteen trillion, three hundred four billion, six hundred forty-five million, forty-four thousand, eleven".
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