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133054554160643 = 2593129073975593
BaseRepresentation
bin11110010000001100101101…
…011011111011111000000011
3122110002220001122120001210012
4132100030231123323320003
5114414431211331120033
61150552230210255135
740011605613525563
oct3620145533737003
9573086048501705
10133054554160643
113943913510a285
1212b0aa44b874ab
135931cb55126cb
1424bdc3658cda3
15105b0c33bd248
hex79032d6fbe03

133054554160643 has 8 divisors (see below), whose sum is σ = 133116213311088. Its totient is φ = 132992902992384.

The previous prime is 133054554160603. The next prime is 133054554160667. The reversal of 133054554160643 is 346061455450331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133054554160643 - 220 = 133054553112067 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133054554160591 and 133054554160600.

It is not an unprimeable number, because it can be changed into a prime (133054554160603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31480055 + ... + 35455647.

It is an arithmetic number, because the mean of its divisors is an integer number (16639526663886).

Almost surely, 2133054554160643 is an apocalyptic number.

133054554160643 is a deficient number, since it is larger than the sum of its proper divisors (61659150445).

133054554160643 is a wasteful number, since it uses less digits than its factorization.

133054554160643 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3991093.

The product of its (nonzero) digits is 7776000, while the sum is 50.

The spelling of 133054554160643 in words is "one hundred thirty-three trillion, fifty-four billion, five hundred fifty-four million, one hundred sixty thousand, six hundred forty-three".

Divisors: 1 2593 12907 3975593 33467851 10308712649 51312978851 133054554160643