Base | Representation |
---|---|
bin | 11000110010001000… |
… | …11110001010010011 |
3 | 1021100021122122201101 |
4 | 30121010132022103 |
5 | 204222202120103 |
6 | 10040143045231 |
7 | 650502631012 |
oct | 143104361223 |
9 | 37307578641 |
10 | 13305504403 |
11 | 5708679434 |
12 | 26b3ba0817 |
13 | 1340779039 |
14 | 903172a79 |
15 | 52d19ba1d |
hex | 31911e293 |
13305504403 has 4 divisors (see below), whose sum is σ = 13523627488. Its totient is φ = 13087381320.
The previous prime is 13305504383. The next prime is 13305504419. The reversal of 13305504403 is 30440550331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30440550331 = 541 ⋅56267191.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13305504403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13305504503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109061451 + ... + 109061572.
It is an arithmetic number, because the mean of its divisors is an integer number (3380906872).
Almost surely, 213305504403 is an apocalyptic number.
13305504403 is a deficient number, since it is larger than the sum of its proper divisors (218123085).
13305504403 is an equidigital number, since it uses as much as digits as its factorization.
13305504403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 218123084.
The product of its (nonzero) digits is 10800, while the sum is 28.
The spelling of 13305504403 in words is "thirteen billion, three hundred five million, five hundred four thousand, four hundred three".
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