Base | Representation |
---|---|
bin | 11110010000001110100100… |
… | …110000011110101111001011 |
3 | 122110010002020011102211011121 |
4 | 132100032210300132233023 |
5 | 114414444311321110034 |
6 | 1150553201001340111 |
7 | 40012006332265201 |
oct | 3620164460365713 |
9 | 573102204384147 |
10 | 133056556035019 |
11 | 39439a72117111 |
12 | 12b0b303497637 |
13 | 5932244194c66 |
14 | 24bdd863b5071 |
15 | 105b18e0011b4 |
hex | 7903a4c1ebcb |
133056556035019 has 2 divisors, whose sum is σ = 133056556035020. Its totient is φ = 133056556035018.
The previous prime is 133056556034921. The next prime is 133056556035043. The reversal of 133056556035019 is 910530655650331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133056556035019 - 213 = 133056556026827 is a prime.
It is a super-2 number, since 2×1330565560350192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133056556035089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66528278017509 + 66528278017510.
It is an arithmetic number, because the mean of its divisors is an integer number (66528278017510).
Almost surely, 2133056556035019 is an apocalyptic number.
133056556035019 is a deficient number, since it is larger than the sum of its proper divisors (1).
133056556035019 is an equidigital number, since it uses as much as digits as its factorization.
133056556035019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5467500, while the sum is 52.
The spelling of 133056556035019 in words is "one hundred thirty-three trillion, fifty-six billion, five hundred fifty-six million, thirty-five thousand, nineteen".
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