Base | Representation |
---|---|
bin | 111101111101111111… |
… | …0100011111111010001 |
3 | 110201111022220122211022 |
4 | 1323323332203333101 |
5 | 4140020041003213 |
6 | 141045015125225 |
7 | 12420521406242 |
oct | 1737376437721 |
9 | 421438818738 |
10 | 133076500433 |
11 | 5148a240478 |
12 | 2195b073815 |
13 | c71a3925a6 |
14 | 6625d06cc9 |
15 | 36dceb9308 |
hex | 1efbfa3fd1 |
133076500433 has 2 divisors, whose sum is σ = 133076500434. Its totient is φ = 133076500432.
The previous prime is 133076500411. The next prime is 133076500489. The reversal of 133076500433 is 334005670331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 132359171344 + 717329089 = 363812^2 + 26783^2 .
It is an emirp because it is prime and its reverse (334005670331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133076500433 - 220 = 133075451857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133076500393 and 133076500402.
It is not a weakly prime, because it can be changed into another prime (133076500493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66538250216 + 66538250217.
It is an arithmetic number, because the mean of its divisors is an integer number (66538250217).
Almost surely, 2133076500433 is an apocalyptic number.
It is an amenable number.
133076500433 is a deficient number, since it is larger than the sum of its proper divisors (1).
133076500433 is an equidigital number, since it uses as much as digits as its factorization.
133076500433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68040, while the sum is 35.
The spelling of 133076500433 in words is "one hundred thirty-three billion, seventy-six million, five hundred thousand, four hundred thirty-three".
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