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13309268201 is a prime number
BaseRepresentation
bin11000110010100101…
…10101000011101001
31021100112201212200022
430121102311003221
5204224133040301
610040355450225
7650546625125
oct143122650351
937315655608
1013309268201
11570a80a209
1226b52b6975
131341496238
14903872585
1552d691d1b
hex3194b50e9

13309268201 has 2 divisors, whose sum is σ = 13309268202. Its totient is φ = 13309268200.

The previous prime is 13309268183. The next prime is 13309268267. The reversal of 13309268201 is 10286290331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7170702400 + 6138565801 = 84680^2 + 78349^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13309268201 is a prime.

It is a super-4 number, since 4×133092682014 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13309568201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6654634100 + 6654634101.

It is an arithmetic number, because the mean of its divisors is an integer number (6654634101).

Almost surely, 213309268201 is an apocalyptic number.

It is an amenable number.

13309268201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13309268201 is an equidigital number, since it uses as much as digits as its factorization.

13309268201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 13309268201 in words is "thirteen billion, three hundred nine million, two hundred sixty-eight thousand, two hundred one".