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133100103121 = 977136233473
BaseRepresentation
bin111101111110101100…
…0100110010111010001
3110201112222022210121221
41323331120212113101
54140042111244441
6141051221045041
712421226131606
oct1737530462721
9421488283557
10133100103121
11514a15a1527
1221966b56781
13c72223778b
1466290cc6ad
1536e00cc8d1
hex1efd6265d1

133100103121 has 4 divisors (see below), whose sum is σ = 133236337572. Its totient is φ = 132963868672.

The previous prime is 133100103113. The next prime is 133100103163. The reversal of 133100103121 is 121301001331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62710176400 + 70389926721 = 250420^2 + 265311^2 .

It is a cyclic number.

It is not a de Polignac number, because 133100103121 - 23 = 133100103113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133100103095 and 133100103104.

It is not an unprimeable number, because it can be changed into a prime (133100103181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68115760 + ... + 68117713.

It is an arithmetic number, because the mean of its divisors is an integer number (33309084393).

Almost surely, 2133100103121 is an apocalyptic number.

It is an amenable number.

133100103121 is a deficient number, since it is larger than the sum of its proper divisors (136234451).

133100103121 is an equidigital number, since it uses as much as digits as its factorization.

133100103121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136234450.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 133100103121 its reverse (121301001331), we get a palindrome (254401104452).

The spelling of 133100103121 in words is "one hundred thirty-three billion, one hundred million, one hundred three thousand, one hundred twenty-one".

Divisors: 1 977 136233473 133100103121